big-bud.cannabis-marijuana.netbig-bud.cannabis-marijuana.netCopyright big-bud.cannabis-marijuana.netbig-bud.cannabis-marijuana.net RSS Generatorhttp://big-bud.cannabis-marijuana.net/marijuanaallseeds/marijuana-seeds-from.php 7-Substituted Metabolites A detailed discussion of the bol-metabolites, which result from the natural material bol-THC, is appropriateTue, 13 Oct 2009 12:00:00 AM GMThttp://big-bud.cannabis-marijuana.net/how to germinate marijuana seeds.php Guterman, PTue, 13 Oct 2009 12:00:00 AM GMThttp://big-bud.cannabis-marijuana.net/culture+marijuana/because of the illegal nature of the apprehension. One individual (arrested twice) involved in smuggling was not arrested in the United States. One of the arrestees was judged at his trial not to be in technical possession of the marijuana (one roach!), and the charges were dismissed.[17] Of the five remaining cases, one was arrested twice. None of the five was incarcerated for his crime; four received suspended sentences, and one was still awaiting trial at the time of the interview. With all of our cases, the detection of the crime was fortuitous; in no case did an undercover agent seek out use and selling. We cite three typical examples of the police accidentally stumbling upon marijuana crimes: A friend of mine whom I turned on felt guilty and told his father about it. His father told the police, and the police followed him to my house. At four a.m., the police rang my doorbell, and, when I answered, beat me up, and then called my parents. I was adjudged a youthful offender, and placed on probation for 14 months. (10 of 31)4/15/2004 1:08:37 AM The Marijuana Smokers - Chapter 11 twenty-year-old college student I was playing pool with another guy, and two cops walked in, took us outside, and searched us, me and my friend, and then they searched our car. One joint was in the car. We were searched illegally; we were handcuffed before they even found anything. The charge is going to be dropped because I'm getting a recommendation from a youth counselor. twenty-one-year-old clerk in a gift shop I was sent one joint from Mexico through the mail. The customs officials delivered the letter to my apartment in person?they had a search warrant?and said that they were going to search my apartment. But I went and got my supply, and gave it to them. They said that they were going to arrest me, but they were willing to cooperate if I did. I supplied them with a name of a dealer?knowing that he was leaving for Canada that day. I wasn't arrested. nineteen-year-old female clerk in a bookstore Post-Arrest Disposition Arrest is only the first step in a long legal process. The questions involved in the postarrest disposition are often extremely complex and technical. The policeman, who operates on the basis of simple guilt or innocence, is frustrated and angered to see one of his cases dismissed on a minor technicality, feeling that the lawyers and judges are trying to abort law and order. However, these formalities were designed to protect the possibly innocent suspect, and they usually err on the side of being overly generous in letting many probably guilty suspects go free, rather than making the mistake of jailing a few possibly innocent suspects. That this happens to such a degree with marijuana charges points to the fact that many judges, district attorneys, and lawyers have lost faith in the justice of the marijuana statutes. A certain degree of leeway is allowed the public officials after arrest; where many decisTue, 13 Oct 2009 12:00:00 AM GMThttp://big-bud.cannabis-marijuana.net/hempseeds/cannagenetics/which there is no change in the gene pool. This means that there can be no evolution. For a test example let us consider a population whose gene pool contains the alleles B and b. Assign the letter c to the frequency of the dominant allele B and the letter d to the frequency of the recessive allele b. [In most cases you will find that c and d are actually notated as p and q by convention in science, but for this example we will use c and d.] The sum of all the alleles must equal 100%. So c + d = 1. All the random possible combinations of the members of a population would equal (c x c) + 2cd + (d x d). Which can also be expressed as: (c+d) X (c+d) We will explain this in detail in moment, but it is best to know it for now. The frequencies of B and b will remain unchanged generation after generation if: 1. The population is large enough. 2. There are no mutations. 295 3. There are no preferences. For example a BB male does not prefer a bb female by its nature. 4. No other outside population exchanges genes with this model. 5. Natural selection must not favor any specific individual. Let us imagine a pool of genes. 12 are B and 18 are b. Now remember The sum of all the alleles must equal 100%. So this means that the total in this case is 12 + 18 = 30. So 30 is 100%. If we want to find the frequencies of B and b and the genotypic frequencies of B, Bb and b then we will have to apply the standard formula that we have just been shown. f (B) = 12/30 = 0.4 = 40% f (b) = 18/30 = 0.6 = 60% Both add to make 100%. Now we know their ratios. So, c + d = 0.4 + 0.6 = 1 We have proven that c + d must equal 1. Very straightforward, yes. 296 Remember that all the random possible combinations of the members of a population would equal (c x c) + 2cd + (d x d), or (c+d) X (c+d) Then, c + d = 0.4 + 0.6 = 1 And (c x c) + 2cd + (d x d) = BB + Bb + bb = .24 + .48 + .30 = 1 This means that the population can increase in size, but the frequencies of B and b will stay the same. Now, suppose we break the 4th law about not introducing another population into this one. Let us say that we add 4 more b. b + b + b + b enter the pool. This brings our total up to 34 instead of 30. What will the gene and genotypic frequencies be? f (B) = 12/34 = .35 = 35 % f (b) = 22/34 = .65 = 65% f (BB) = .12, f (Bb) = .23 and f (bb) = .42 Oppss, .42 does not equal 1. This means that the Equilibrium law fails if the 4th law is not met. When the new genes entered the pool it resulted in a change of the population?s gene frequencies. However if 297 no other populations where introduced then the frequency of .42 would be maintained generation after generation. However we would like to point out that we used a very small pool in the above example. If the pool were much larger then the number of changes, even if one or two new genes jumped in, would be insignificant. You could calculate it, but the change would be on an extremely low leveTue, 13 Oct 2009 12:00:00 AM GMThttp://big-bud.cannabis-marijuana.net/buy-cannabis-seeds.php This in turn undergoes a photoinduced dehydration and ring closure to give the highly fluorescent hydroxyphenanthrene 179Tue, 13 Oct 2009 12:00:00 AM GMThttp://big-bud.cannabis-marijuana.net/test_cannabis_Big_Bud.php SYNTHESIS OF THC ANALOGS 106 The cannabis plant, being a complex mixture, is unlikely to be used as a marketable drug; therefore, the future of therapeutic agents from cannabinoids undoubtedly lies in the syntheticsThu, 07 Jan 2010 12:00:00 AM GMThttp://big-bud.cannabis-marijuana.net/seeddirect.phpctivity, especially creative pastimes. Good for parties also. Very social.? ? Castanza" "AK47 (Blue Bird Coffee shop): ?Nice & complex high. Flavorful taste. Elements of both sides of the cannabis spectrum are clearly pronounced.? - Prince Caspian ?These dark green buds are very resin-y and have bunches of short, red hairs throughout. Some buds are less green with more hairs. This hydro has a very pungent, sweet, skunky green smell that will make your mouth water and will put a smile on your face. One or two small, crystally stems to chew on are all the non-smokables you get. The fluffy, compact buds break up nicely and will leave plenty of polleny crystals on your fingers. The smooth, skunky smoke tastes sweet and flowery, though it is expansive in the lungs and a bit of a cougher. Overall, the taste is outstanding. Not overly visual, a strongly mellowing high ensues that is conducive to listening to music, watching a movie or maybe hanging out at a Coffeeshop. This bud could get you to open your bag of Oreo's or order 'patat' on your way home.? - Dankmaster" "?If a sledge hammer to the head is what your looking for then AK is your girl how it grows yield and buds depends on which side of sativa/indica spectrum is more dominant indica ones one grow short and yielded large fluffy semi dense buds at 50 days very crystally with a spicy smell and woody like taste its high was strong and lasting but not like the sativa. The sativa is longer but is the better one. It produced hard size pine cone shaped buds at 70 days super crystally (not like G13xNL that?s the queen of resin) with very little leaf a very nice spicy smell and woody taste that would take your lungs inside out and gasping for breath really strong more up but still slammin hard lasting high I got a headache from smoking too much of this one:)... that?s all I know..Hope this helps your choice.? - Dankmaster" "?How it grows and yields depends on which side of spectrum is more dominant. I have 2 mothers: one mostly indica and shorter nodes large nuggs with a fat top it built buds much different than the other that went the usual way sorta stacked single blade leaves it didn?t decrease in blade numbers with lots of clusters had great gland production and a killer spicy wood-like smell. It flowered for about 50 days potency was strong and UP. The mostly sativa grew a bit larger and longer nodes but flowered much better than the indica, solid dense large nuggs covered in twice as much glands as the other. It flowered for 75 days. The high on this is the best; the smoke will tear your lungs apart and will smash ya within minutes. I found when I smoke too much of this one I would get a headache. Guess its very strong but not strong enough like G13xNL and plan on breeding my AK indica with G13xNL pollen that was I given its already been given the name Uzi... Well hope that helps ya out its 2nd best in my book and nothing beats the G13-NL.? ? Dankmaster" "?This type oTue, 13 Oct 2009 12:00:00 AM GMThttp://big-bud.cannabis-marijuana.net/marijuana_pictures_from_blueberry_plants.phpthe recessive trait, the unknown genotype is heterozygous 3. If ALL the offspring have the dominant trait, the unknown genotype is homozygous dominant 4. Large numbers are needed for reliable results. And this is your first step into the world of breeding because: (1) When you breed plants you want to continue a trait. Something that you like to see on your plant or taste with your plant or the height of your plant. (2) When you want to continue that trait you must know if it is Homozygous Dominant, Heterozygous or Homozygous Recessive. (3) You can find that out by running a test cross. So the question may arise - How do I breed for several traits, like taste, smell, vigor and color? Well that is a big question. Maybe to understand more about that we should learn more about Hardy- Weinberg Equilibrium. 303 Hardy-Weinberg Equilibrium Part 2 If we mate two individuals that are heterozygous (e.g., Bb) for a trait what will we find? (Let?s make the Punnett square). Look at that. In this group our resulting offspring will be: 1 BB, 2 Bb, 1 bb This means that: 25% of their offspring are homozygous for the dominant allele (BB). 50% are heterozygous like their parents (Bb) and 25% are homozygous for the recessive allele (bb). Now look at this closely. Unlike their parents Bb Bb, 25% will express the recessive phenotype bb. So if we where given two parents that displayed golden bud but where BOTH heterozygous for that trait Bb, we would also produce offspring that have silver bud. But since Bb is dominant in both parents, neither of the parents would display the phenotype for silver bud. This is really what breeding is all about. When we have a strain that we want to keep, how do we know that the parts we want to 304 keep will actually be kept in our breeding process? This is where the test cross comes in. If we create seeds from a strain that we bought in a seed-bank how can we be sure that the offspring will have the character that we like? Well the facts are this. If the trait(s) we wish to continue are Homozygous Dominant (BB) in both the parent plants then there is no way we can produce a recessive genotype for that trait in the offspring. We already explained this in the previous section. Let?s prove this: Look! It is impossible for the recessive trait to appear. And if both parents contained the recessive trait we can not produce the dominant trait. Let us see this in action too. There we proved that too. So now we are starting to understand that in order to breed a trait properly we must know if it is Homozygous or Heterozygous or Homozygous Recessive before we can understand what it is we are doing and PREDICT THE RESULTS BEFORE THEY HAPPEN. And 305 this ladies and gentlemen is what breeding is all about - Understanding a trait?s genotype, predicting the outcome of a cross and LOCKING DOWN TRAITS. So how can we lock down a trait you might ask? Well we will cover this later after we understSun, 24 Jan 2010 12:00:00 PM GMThttp://big-bud.cannabis-marijuana.net/mauiwowiecannabis.php, 4495 (1970)Sat, 17 Oct 2009 12:00:00 PM GMThttp://big-bud.cannabis-marijuana.net/seads-jack-herrer.php7 232 The Total Synthesis of Cannabinoids During their studies on cannabielsoin (152) Uliss et alSat, 24 Oct 2009 12:00:00 AM GMT